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Sagot :
Given:
The nth term of a sequence is:
[tex]n^2+5[/tex]
To find:
The first five terms of the given sequence.
Solution:
The given sequence is:
[tex]a_n=n^2+5[/tex]
For n=1,
[tex]a_1=1^2+5[/tex]
[tex]a_1=1+5[/tex]
[tex]a_1=6[/tex]
For n=2,
[tex]a_2=2^2+5[/tex]
[tex]a_2=4+5[/tex]
[tex]a_2=9[/tex]
For n=3,
[tex]a_3=3^2+5[/tex]
[tex]a_3=9+5[/tex]
[tex]a_3=14[/tex]
For n=4,
[tex]a_4=4^2+5[/tex]
[tex]a_4=16+5[/tex]
[tex]a_4=21[/tex]
For n=5,
[tex]a_5=5^2+5[/tex]
[tex]a_5=25+5[/tex]
[tex]a_5=30[/tex]
Therefore, the first five terms of the given sequence are 6, 9, 14, 21, 30.
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