Answered

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a. The first five terms of n^2 + 5 are

Sagot :

Given:

The nth term of a sequence is:

[tex]n^2+5[/tex]

To find:

The first five terms of the given sequence.

Solution:

The given sequence is:

[tex]a_n=n^2+5[/tex]

For n=1,

[tex]a_1=1^2+5[/tex]

[tex]a_1=1+5[/tex]

[tex]a_1=6[/tex]

For n=2,

[tex]a_2=2^2+5[/tex]

[tex]a_2=4+5[/tex]

[tex]a_2=9[/tex]

For n=3,

[tex]a_3=3^2+5[/tex]

[tex]a_3=9+5[/tex]

[tex]a_3=14[/tex]

For n=4,

[tex]a_4=4^2+5[/tex]

[tex]a_4=16+5[/tex]

[tex]a_4=21[/tex]

For n=5,

[tex]a_5=5^2+5[/tex]

[tex]a_5=25+5[/tex]

[tex]a_5=30[/tex]

Therefore, the first five terms of the given sequence are 6, 9, 14, 21, 30.

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