Answered

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A balloon, inflated in an air-conditioned room at 27.0°C, has a volume
of 4.50.L. It is heated to a temperature of 57.0°C. What is the new
volume of the balloon if the pressure remains constant?

Sagot :

samueladesida43

Answer:

4.95L

Explanation:

Using Charle's law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question, the following information was given:

V1 = 4.50L

V2 = ?

T1 = 27°C = 27 + 273 = 300K

T2 = 57°C = 57 + 273 = 330K

Using V1/T1 = V2/T2

4.50/300 = V2/330

Cross multiply

300 × V2 = 4.5 × 330

300V2 = 1485

V2 = 1485 ÷ 300

V2 = 4.95L

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