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The tens digit is missing from the three-digit number 8 _ 9. If the tens digit is to be randomly selected from the ten different digits from 0 to 9, what is the probability that the resulting three digit number will be a multiple of 9?

Sagot :

jcherry99

Step-by-step explanation:

Only 1 number works. 1 will make 819 which is divisible by 9.

Since it is 1 of ten numbers can go in the blank, the answer is 1/10 which is 0.1

The 10 number choices are

0,1,2,3,4,5,6,7,8,9

The only one that works is 1 as I've stated.

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