Consider the below figure attached with this question.
Given:
The transformation is:
[tex]f(x,y)=(-2x,-3y+1)[/tex]
The range is (4,-2), (2, −5), (−6, 4).
To find:
The domain of the transformation.
Solution:
We have,
[tex]f(x,y)=(-2x,-3y+1)[/tex]
For the point (4,-2),
[tex](-2x,-3y+1)=(4,-2)[/tex]
On comparing both sides, we get
[tex]-2x=4[/tex]
[tex]x=\dfrac{4}{-2}[/tex]
[tex]x=-2[/tex]
And,
[tex]-3y+1=-2[/tex]
[tex]-3y=-2-1[/tex]
[tex]-3y=-3[/tex]
[tex]y=\dfrac{-3}{-3}[/tex]
[tex]y=1[/tex]
So, the domain of (4,-2) is (-2,1).
Similarly,
For the point (2,-5),
[tex](-2x,-3y+1)=(2,-5)[/tex]
On comparing both sides, we get [tex]x=-1,y=2[/tex]. So, the domain of (2,-5) is (-1,2).
For the point (-6,4),
[tex](-2x,-3y+1)=(-6,4)[/tex]
On comparing both sides, we get [tex]x=3,y=-1[/tex]. So, the domain of (-6,4) is (3,-1).
So, the domain of the given transformation is (-2, 1), (-1, 2), (3, -1).
Therefore, the correct option is A.
