Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A cube of aluminum of mass 4kg is immersed totally in kerosene. It was found that 50g of kerosene was displaced, if the density of the kerosene is 13.5kg/m³, calculate the length and density of the aluminum cube​

Sagot :

onyebuchinnaji

The length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively

Volume of the aluminum

The volume of the aluminum is equal to the weight of the kerosene displaced.

V = 0.05 kg / 13.5 kg/m³

V = 3.7 x 10⁻³ m³

Density of the aluminum

density = mass/volume

density = 4 kg / 3.7 x 10⁻³ m³

density = 1,081.1 kg/m³

Length of the aluminum

V = L³

L = ∛V

L = ∛(3.7 x 10⁻³)

L = 0.1546 m

L = 15.46 cm

Thus, the length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively.

Learn more about density here: https://brainly.com/question/6838128

#SPJ1

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.