Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A cube of aluminum of mass 4kg is immersed totally in kerosene. It was found that 50g of kerosene was displaced, if the density of the kerosene is 13.5kg/m³, calculate the length and density of the aluminum cube​

Sagot :

onyebuchinnaji

The length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively

Volume of the aluminum

The volume of the aluminum is equal to the weight of the kerosene displaced.

V = 0.05 kg / 13.5 kg/m³

V = 3.7 x 10⁻³ m³

Density of the aluminum

density = mass/volume

density = 4 kg / 3.7 x 10⁻³ m³

density = 1,081.1 kg/m³

Length of the aluminum

V = L³

L = ∛V

L = ∛(3.7 x 10⁻³)

L = 0.1546 m

L = 15.46 cm

Thus, the length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively.

Learn more about density here: https://brainly.com/question/6838128

#SPJ1

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.