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Adya and Ashley complete a work separately in 20 and 25 days respectively. After 10 days of their working together, they both left then Amber came and completed the remaining work in 3 days. If Amber alone would do the work, calculate how many days he would take to complete the work.?​

Sagot :

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Number of days Adya took to complete the work = 20

Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]

Number of days Ashley took to complete the work = 25

Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]

So,

Total work by Adya & Ashley in 1 day =

[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]

•°• Their total work in 10 days =

[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]

Now,

The work left to be completed =

[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]

From this we know that,

Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.

So,

Time taken by Amber to complete the whole work =

[tex]3 \times 10 \\ = 30 \: \: days[/tex]

↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.

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