Hey there!
[tex]\mathsf{x^2 - 11 = 25}[/tex]
[tex]\large\textsf{ADD 11 to BOTH SIDES}[/tex]
[tex]\mathsf{x^2 - 11 + 11 = 25 + 11}[/tex]
[tex]\large\textsf{CANCEL out: -11 + 11 because that gives you 0}[/tex]
[tex]\large\textsf{KEEP: 25 + 11 because that helps solve for the x-value}[/tex]
[tex]\mathsf{25 + 11 = \bf 36}[/tex]
[tex]\large\textsf{NEW EQUATION: }\mathsf{x^2=36}[/tex]
[tex]\large\textsf{Take the square root of the number (36)}[/tex]
[tex]\mathsf{x = \pm \sqrt{36}}[/tex]
[tex]\mathsf{\pm = \boxed{\bf plus-or-minus}}[/tex]
[tex]\mathsf{x = \sqrt{-36}\rightarrow \bf -6}[/tex]
[tex]\large\textsf{or}[/tex]
[tex]\mathsf{x = \sqrt{36} = \bf 6}[/tex]
[tex]\boxed{\boxed{\huge\textsf{Answer: \bf x = 6 or x = -6}}}\huge\checkmark[/tex]
[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
x² - 11 = 25
Add 11 to both sides.
x² - 11 + 11 = 25 + 11
Cancle out the 11 because when we add -11 to 11 that gives 0. On other side add 25 and 11 we get 36.
x² = 36
Take the square root of both sides of the equation and remember to use both positive and negative roots.
√x² = ± √36
x = ± 6
Write the solutions, one with a+ sign and one with a- sign.
[tex] x_1 = 6[/tex]
[tex]x_2 = -6[/tex]
This equation has two solutions which are :-
[tex] x_1 = 6[/tex]and [tex]x_2 = -6[/tex]
