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Sagot :
Given:
The quadratic function is:
[tex]f(x)=x^2+3x-4[/tex]
To find:
The zeros of the given quadratic function.
Solution:
We have,
[tex]f(x)=x^2+3x-4[/tex]
Splitting the middle term, we get
[tex]f(x)=x^2+4x-x-4[/tex]
[tex]f(x)=x(x+4)-1(x+4)[/tex]
[tex]f(x)=(x+4)(x-1)[/tex]
For zeros, [tex]f(x)=0[/tex].
[tex](x+4)(x-1)=0[/tex]
[tex]x=-4,1[/tex]
Therefore, the correct option is (b).
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