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A car travelling at 10ms ,acceleration uniformly at 2ms what will be its velocity after 5s?​

Sagot :

mistressofdark

[tex]we \: know \: that \\ acceleration = \frac{(final \: velocity - initial \: velocity)}{time} \\ = > a = \frac{(v - u)}{t} \\ = > 2m {s}^{ - 2} = \frac{{(v - 10m {s}^{ - 1} })}{5s} \\ = > 2m {s}^{ - 2} \times 5s = v - 10m {s}^{ - 1} \\ = > 10m {s}^{ - 1} = v - 10m {s}^{ - 1} \\ = > 10m {s}^{ - 1} + 10m {s}^{ - 1} = v \\ = > 20m {s}^{ - 1} = v \\ = > 20m {s}^{ - 1} = initial \: velocity[/tex]

Hope it helps!!

Thanks!!

herronrosealexis

Answer:

20 ms

Explanation:

You know

acceleration=2ms        initial Velocity=10ms          Time=5s

We are finding Final V

Use the equation     Final v = (a x t) + initial v

2 x 5 = 10

10 + 10 = 20

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