Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Find the slope of a line parallel to a line that contains the points (9, -3) and (-3, 8).

Sagot :

Lanuel

Answer:

[tex] Slope, \ m = \frac {11}{-12} [/tex]

Explanation:

Given the following points;

Points on the x-axis (x1, x2) = (9, -3)

Points on the y-axis (y1, y2) = (-3, 8)

To find the slope of a line parallel to a line;

Mathematically, the slope of a line is given by the formula;

[tex] Slope, \ m = \frac {Change \; in \; y-axis}{Change \; in \; x-axis} [/tex]

[tex] Slope, \ m = \frac {y_{2} - y_{1}}{x_{2} - x_{1}} [/tex]

Substituting into the formula, we have;

[tex] Slope, \ m = \frac {8 - (-3)}{-3 - 9} [/tex]

[tex] Slope, \ m = \frac {8 + 3}{-3 - 9} [/tex]

[tex] Slope, \ m = \frac {11}{-12} [/tex]

Therefore, the slope of the parallel line is -11/12.

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.