Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Find the slope of a line parallel to a line that contains the points (9, -3) and (-3, 8).

Sagot :

Lanuel

Answer:

[tex] Slope, \ m = \frac {11}{-12} [/tex]

Explanation:

Given the following points;

Points on the x-axis (x1, x2) = (9, -3)

Points on the y-axis (y1, y2) = (-3, 8)

To find the slope of a line parallel to a line;

Mathematically, the slope of a line is given by the formula;

[tex] Slope, \ m = \frac {Change \; in \; y-axis}{Change \; in \; x-axis} [/tex]

[tex] Slope, \ m = \frac {y_{2} - y_{1}}{x_{2} - x_{1}} [/tex]

Substituting into the formula, we have;

[tex] Slope, \ m = \frac {8 - (-3)}{-3 - 9} [/tex]

[tex] Slope, \ m = \frac {8 + 3}{-3 - 9} [/tex]

[tex] Slope, \ m = \frac {11}{-12} [/tex]

Therefore, the slope of the parallel line is -11/12.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.