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Find the slope of a line parallel to a line that contains the points (9, -3) and (-3, 8).

Sagot :

Lanuel

Answer:

[tex] Slope, \ m = \frac {11}{-12} [/tex]

Explanation:

Given the following points;

Points on the x-axis (x1, x2) = (9, -3)

Points on the y-axis (y1, y2) = (-3, 8)

To find the slope of a line parallel to a line;

Mathematically, the slope of a line is given by the formula;

[tex] Slope, \ m = \frac {Change \; in \; y-axis}{Change \; in \; x-axis} [/tex]

[tex] Slope, \ m = \frac {y_{2} - y_{1}}{x_{2} - x_{1}} [/tex]

Substituting into the formula, we have;

[tex] Slope, \ m = \frac {8 - (-3)}{-3 - 9} [/tex]

[tex] Slope, \ m = \frac {8 + 3}{-3 - 9} [/tex]

[tex] Slope, \ m = \frac {11}{-12} [/tex]

Therefore, the slope of the parallel line is -11/12.

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