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Sagot :

leena

Hi there!

[tex]\large\boxed{(4y + 1)(2y + 1)}[/tex]

8y² + 6y + 1

Factored form is as such:

(ax + b)(cx + d), where:

a · c = 8

bc + da = 6

b · d = 1

After guessing and checking, we get:

(4y + 1)(2y + 1)

Step-by-step explanation:

By splitting middle term method:

8y² + 6y + 1

= 8y² + 2y + 4y + 1

= 2y(4y + 1) + 1(4y + 1)

= (2y + 1) (4y + 1)

I guess this is easier