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A 10cm long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.35 Ω. Pulling the wire with a force of 1.0 N causes 4.0 W of power to be dissipated in the circuit.
a. What is the speed of the wire when pulled with a force of 1.0 N?
b. What is the strength of the magnetic field?

Sagot :

okpalawalter8

Answer:

a)  [tex]v=4.0m/s[/tex]

b)  [tex]B=2.958T[/tex]

Explanation:

From the question we are told that:

Wire Length [tex]l=10cm=>0.10m[/tex]

Resistance [tex]R=0.35[/tex]

Force [tex]F=1.0N[/tex]

Power [tex]P=4.0W[/tex]

a)

Generally the equation for Power is mathematically given by

[tex]P=Fv[/tex]

Therefore

[tex]v=\frac{P}{F}[/tex]

[tex]v=\frac{4.0}{1.0}[/tex]

[tex]v=4.0m/s[/tex]

b)

Generally the equation for Magnetic Field is mathematically given by

[tex]B=\frac{\sqrt{PR}}{vl}[/tex]

[tex]B=\frac{\sqrt{4*0.35}}{4*0.10}[/tex]

[tex]B=2.958T[/tex]

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