Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A personal trainer is interested in the typical physical activity of her clients. She asked a sample of her customers how many hours of exercise they get each week, and recorded the data below.
Describe her findings using everything you've learned about measures of central tendency, measures of variability, and frequency distributions.
х = 2, 4, 5, 5, 7, 5, 3, 3, 4, 4
Include mean, mode, median, variance, standard deviation and type of distribution.

Sagot :

fichoh

Answer:

Mean = 4.2

Mode = 4 and 5

Median = 4

Variance, = 1.956

Standard deviation = 1.395

Step-by-step explanation:

Given the data :

х = 2, 4, 5, 5, 7, 5, 3, 3, 4, 4

Ordered data : 2, 3, 3, 4, 4, 4, 5, 5, 5, 7

The mean, xbar = Σx / n ; n = sample size = 10

xbar = 42 / 10 = 4.2

The mode : 4 and 5 (most frequently occurring values) (3 frequency each) = BIMODAL

The median = 1/2(n+1)th term

Median = 1/2(11)th term = 5.5 th term

Median = (5th + 6th term) /2 = (4 + 4) / 2 = 4

Variance , s² = Σ(x - xbar)²/(n-1)

Using a calculator :

Variance, s² = 1.956

Standard deviation, s = √variance = √s² = √1.956 = 1.395

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.