Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
a) θ = 11 rad, θ = 1.75 rev., b) w = 9 rad / s, c) θ = 7.17 rev
Explanation:
This is a rotation kinematics exercise
θ = θ₀ + w₀ t + ½ α t²
They indicate the initial angular velocity w₀ = 2.00 rad / s, the angular acceleration α = 3.50 rad / s² and that at the initial instant θ₀ = 0
a) let's find the rotated angle
θ = 0 + 2.00 2.00 +1/2 3.5 2²
θ = 11 rad
let's reduce 2π rad = 1 rev
θ = 11 rad (1 rev / 2π rad)
θ = 1.75 rev.
b) angular velocity
w = w₀ + α t
w = 2.00 + 3.50 2
w = 9 rad / s
c) the angular displacement to reach this speed
w² = w₀² + 2 α θ
in this case they indicate that w = 2 9 = 18 rad / s
θ = [tex]\frac{w^2 - w_o^2}{2 \alpha }[/tex]
θ = [tex]\frac{18^2 - 2^2 }{2 \ 3.5 }[/tex]
θ = 45.7 rad
let's reduce to rev
θ = 45.7 rad (1rev / 2π rad)
θ = 7.17 rev
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
