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An arbitrarily curved wire that carries a current between two endpoints in the presence of a uniform magnetic field will experience the same net magnetic force as a straight wire carrying the same current between the same endpoints. Essentially, any forces experienced by parts of the wire that curve or twist away from the straight-line path are canceled out by forces on sections that curve back toward the original path. Furthermore, if the wire forms a closed loop in between the endpoints, the net force on the closed loop is zero.
Using this result, consider a town where the Earth's magnetic field has a magnitude of 48.8 uT. The magnetic field vector lies in a vertical plane defined by the north-south and up-down axes, and it points 60.00 below the northward direction. In this town, storefront window lies along the north-south vertical plane, and the window is a neon sign (which is a thin current-carrying discharge out the word "OINER" hotwoon the two points What is the s0th co (in u) n the nooe eig2 Ctale ast to he the e to be -axis, and south to ha De net vector magnetic f .. include units in your answer.)


Sagot :

Answer:

The solution can be defined as follows:

Explanation:

Calculating the magnetic force:

[tex]\to \overrightarrow{F_B}=ILB \sin \beta\\\\[/tex]

Calculating the length:

[tex]\to L=\sqrt{(1.39)^2+(0.85)^2}=1.63\ m\\\\[/tex]

[tex]\tan \theta=\frac{0.85}{1.39}\\\\\theta=\tan^{-1} (\frac{0.85}{1.39})\\\\=31.45^{\circ}\\\\\beta =60+\theta\\\\=60+31.45\\\\= 91.45^{\circ}\\\\ \overrightarrow{F_B} =(36.6\times 10^{-3}) (1.63) (48.8\times 10^{-6})\sin 91.45^{\circ}\\\\=2.91 \times 10^{-6}\ N\\\\=2.91 \ \mu \ N[/tex]

Find the graph file in the attachment.

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