At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
The rate of appearance of I2(g)=0.225M/s
Explanation:
We are given that
[tex]2HI\rightarrow H_2+I_2[/tex]
[tex]\frac{d[HI]}{dt}=-0.45M/s[/tex]
We have to find the rate of appearance of I2(g).
We know that
Rate of reaction=[tex]-\frac{1}{2}\frac{d[HI]}{dt}=\frac{d[I_2]}{dt}=\frac{d[H_2]}{dt}[/tex]
Therefore,
[tex]-\frac{1}{2}\frac{d[HI]}{dt}=\frac{d[I_2]}{dt}[/tex]
Substitute the values
We get
[tex]-\frac{1}{2}\times (-0.45)=\frac{d[I_2]}{dt}[/tex]
[tex]\frac{d[I_2]}{dt}=0.225M/s[/tex]
Hence, the rate of appearance of I2(g)=0.225M/s
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.