Answered

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A horizontal pipe with water flowing through it has a circular cross section that varies in diameter. the diameter at the wide section is 4 times the diameter at the narrow section. If the rate of flow of the water in the narrow section is 9.0 L/min, the rate of flow of the water in the wide section is:_________

Sagot :

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Answer:

9.0 L/min

Explanation:

From the given information, the flow rate in the wider section appears to four times that of the narrow section.

Since the flow rate for a pipe at any time (t) = Area (A) × speed (V)

we can say that:

[tex]A_wV_w = A_nV_n[/tex]

Then, the flow rate in the wider section will also be 9.0 L/min. This is because the mass flow rate must be kept constant regardless of the changes in the size of the cross-sectional area.

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