Answer:
B) 28 inches.
Step-by-step explanation:
After 1/8 of a ribbon is thrown away, the remaining part is cut into two pieces whose lengths are in the ratio 4 : 5.
And we want to find the length of the shorter ribbon from the two remaining pieces.
We are given that 9 inches of the original ribbon was thrown away. Since this is 1/8 of the total length, we can write that:
[tex]\displaystyle \frac{1}{8}L=9[/tex]
Where L represents the total length of the ribbon.
Solve for the total length:
[tex]\displaystyle L=72\text{ inches}[/tex]
So, the original length of the ribbon was 72 inches.
Since we threw away 9 inches of it, we now only have 63 inches.
This is then cut into two pieces in a ratio of 4 : 5. Let x represent the constant. Thus:
[tex](4x)+(5x)=63[/tex]
Solve for x:
[tex]9x=63\Rightarrow x=7[/tex]
Hence, the two remaining ribbons measure 28 inches and 35 inches.
Therefore, our answer is B.
