Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Fe-54 = 5.845%
Fe-56 = 91.754%
Fe-58 = 2.119%

(Please help)
Calculate the average atomic mass/ given their percent abundance

Sagot :

samueladesida43

Answer:

55.768

Explanation:

The following information is given in this question:

Fe-54 = 5.845%

Fe-56 = 91.754%

Fe-58 = 2.119%

First, we convert from percentage abundance to decimal abundance

Fe-54 = 5.845% = 0.05845

Fe-56 = 91.754% = 0.91754

Fe-58 = 2.119% = 0.02119

To find the average atomic mass of iron (Fe), we multiply each isotopes' decimal abundance by its mass no and find the sum as follows:

Average atomic mass = (0.05845 × 54) + (0.91754 × 56) + (0.02119 × 58)

Average atomic mass = 3.1563 + 51.38224 + 1.22902

Average atomic mass = 55.768

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.