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A bus leaves Riverside for Springfield and averages only 48 mph. Ten minutes later Smith leaves Riverside for Springfield traveling 64 mph in his car. How long before he overtakes the bus?

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Answer:

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Step-by-step explanation:

varshamittal029

Smith overtakes the bus at (2/3)×60=40 minutes

What is speed?

A body is said to have speed v if he travels v distance in unit time.

How to solve it?

Suppose that Smith overtakes the bus at a time 't'. Then the distance traveled by bus is 48×t m and that by Smith is 64×(t-1/6).

Smith needs t-1/6 hours to reach the same position that the bus is in.

Since Smith leaves ten minutes later hence it takes t-1/6 hours for him to overtake the bus.

Because 10 minutes is equal to 10/60=1/6 hour.

So,

48×t=64×(t-1/6)

⇒t=2/3

Hence, Smith overtakes the bus at (2/3)×60=40 minutes

Learn more about speed and distance here-

brainly.com/question/12759408

#SPJ2

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