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At a temperature of -25 °C, a sample of gas in a rigid container exerts a pressure of 55.8 kPa. At what temperature will the pressure reach 145 kPa?

Sagot :

The required temperature of the gas sample is -64.96 °C.

What is ideal gas equation?

Ideal gas equation gives idea about the behavior of gas at different condition & represented as:

PV = nRT.

From the above equation it is clear that relation between temperature and pressure for this question is:

P₁/T₁ = P₂/T₂, where

P₁ & T₁ are the initial pressure and temperature.

P₂ & T₂ are the final pressure and temperature.

On putting values, we get

T₂ = (145)(-25) / (55.8) = -64.96 °C

Hence required temperature of the sample is -64.96 °C.

To know more about ideal gas equation, visit the below link:
https://brainly.com/question/1056445

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