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PLEASE HURRY
perform the following series of rigid transformations on ∆abc
translate triangle abc by moving it 5 units to the right and 2 units up
Draw the line y=-x and reflect Triangle A’B’C’ across the line
Rotate A’’B’’C’’ counterclockwise about the fact origin by 270 degress

PLEASE HURRY Perform The Following Series Of Rigid Transformations On Abc Translate Triangle Abc By Moving It 5 Units To The Right And 2 Units Up Draw The Line class=

Sagot :

Answer:

Step-by-step explanation:

Coordinates of the vertices of ΔABC,

A(-6, -1), B(-3, -3), C(-1, -2)

Step - 1

Rule for the translation of a point (x, y) by 'h' units right and 'k' units upwards,

A(x, y) → A(x + h, y + k)

If ΔABC is translated by 5 units right and 2 units up, image points will be,

A(-6, -1) → H(-6 + 5, -1 + 2)

            → H(-1, 1)

B(-3, -3) → J(-3 + 5, -3 + 2)

             → J(2, -1)  

C(-1, -2) → K(-1 + 5, -2 + 2)

            → K(4, 0)

Step - 2

If the image triangle HJK is reflected across a line [tex]y=-x[/tex], rule for the reflection will be,

H(x, y) → A'(-y, -x)

By this rule,

H(-1, 1) → A'(-1, 1)

J(2, -1) → B'(1, -2)

K(4, 0) → C'(0, -4)

Step - 3

Rule for the rotation of a point 270° counterclockwise about the origin,

A'(x, y) → A"(y, -x)

By this rule, image points of ΔA'B'C' will be,

A'(-1, 1) → A"(1, 1)

B'(1, -2) → B"(-2, -1)

C'(0, -4) → C"(-4, 0)

Now we can graph the image triangle A"B"C".

View image eudora

Answer:

(∠ABC) 108 (for all)

(∠ACB) 27 (for all)

(∠CAB) 45 (for all)

Step-by-step explanation:

View image yogirlsv
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