Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.
Explanation:
Given: Mass of Mg = 2.3 g
Pressure = 2 atm
Temperature = 298 K
The reaction equation is as follows.
[tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]
This shows that 1 mole of Mg gives 1 mole of [tex]H_{2}[/tex].
Hence, moles of Mg for the given mass is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{2.3 g}{24.30 g/mol}\\= 0.095 mol[/tex]
Hence, 0.095 moles of Mg will give 0.095 moles of [tex]H_{2}[/tex].
Formula used to calculate volume is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into the above formula as follows.
[tex]PV = nRT\\2 atm \times V = 0.095 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{0.095 mol \times 0.0821 L atm/mol K \times 298 K}{2 atm}\\= 1.16 L[/tex]
Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.