Answered

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its
A bag contains 5 green candies and 7 blue candies.
A piece of candy is selected at random, put back into the bag, and then
another piece of candy is chosen.
What is the probability that both pieces are green?

Sagot :

MrRoyal

Answer:

[tex]P(Green\ and\ Green) = \frac{25}{144}[/tex]

Step-by-step explanation:

Given

[tex]Green=5[/tex]

[tex]Blue = 7[/tex]

Required

[tex]P(Green\ and\ Green)[/tex]

This is calculated as:

[tex]P(Green\ and\ Green) = P(Green) * P(Green)[/tex]

Since, it is a probability with replacement, we have:

[tex]P(Green\ and\ Green) = \frac{Green}{Total} * \frac{Green}{Total}[/tex]

So, we have:

[tex]P(Green\ and\ Green) = \frac{5}{12} * \frac{5}{12}[/tex]

[tex]P(Green\ and\ Green) = \frac{25}{144}[/tex]

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