Answer:
a) P(man asked for a raise) = 0.21.
b) P(man received raise, given he asked for one) = 0.6.
c) P(man asked for raise and received raise) = 0.126.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
21% asked for a raise, so:
P(man asked for a raise) = 0.21.
Question b:
Event A: Asked for a raise.
Event B: Received a raise:
21% had asked for a raise and 60% of the men who had asked for a raise received the raise:
This means that [tex]P(A) = 0.21, P(A \cap B) = 0.21*0.6[/tex], thus:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.21*0.6}{0.6} = 0.6[/tex]
P(man received raise, given he asked for one) = 0.6.
Question c:
[tex]P(A \cap B) = 0.21*0.6 = 0.126[/tex]
P(man asked for raise and received raise) = 0.126.
