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Assume the random variable X is normally​ distributed, with mean of 50 and a standard deviation of 9. Find the 9th percentile.

Sagot :

madethisfortwitch1

Answer:

37.94

Step-by-step explanation:

the 9th percentile is equal to a zscore of -1.34

-1.34=(x-50)/9

x=37.94

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