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In the figure above the ratio of the area of WXZ to the area of WYZ is 7:2. If XY = 21, what is the length of segment WY?

In The Figure Above The Ratio Of The Area Of WXZ To The Area Of WYZ Is 72 If XY 21 What Is The Length Of Segment WY class=

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Because ∆XZW and WYZ is the same height and

Because ∆XZW and WYZ is the same height and the are of ∆WXZ to the the WYZ

[tex]so \:( \frac{1}{2}xw \times h)( \frac{1}{2} w)=7:2[/tex]

Because xy=21

[tex]so \: WY=2 \frac{1}{2}(7 + 2x2) \\ = 21 \frac{1}{2}p \times 2 \\ =\small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: WY=\frac{14}{3}\:\:\:\: }}}}[/tex]

The length of the line segment WY is [tex]\frac{14}{3}[/tex] unit.

What is the area of triangle?

The area of a triangle is defined as the total region that is enclosed by the three sides of any particular triangle.

What is the formula for the area of triangle?

Area of triangle = (1/2)base × height

According to the given question.

The ratio of the area of triangle WXZ to the area of triangle WYZ is 7:2.

Since, the height WZ for both the triangles WXZ and WYZ is same.

Let, WZ = h

Therefore, the ratio of the area of the triangles is given by  

 [tex]\frac{\frac{1}{2}WX(h) }{\frac{1}{2}(WY)(h) } =\frac{7}{2}[/tex]

⇒ [tex]\frac{WX}{WY} =\frac{7}{2}[/tex]

⇒ [tex]WX = \frac{7}{2} WY..(i)[/tex]

Since, in the given figure

[tex]XY = WY + WX[/tex]

⇒ [tex]21 = WY + \frac{7}{2} WY[/tex]   (from i)

⇒ [tex]21 = \frac{9}{2}WY[/tex]

⇒ [tex]WY = \frac{14}{3}[/tex]

Hence, the length of the line segment WY is [tex]\frac{14}{3}[/tex] unit.

Find out more information about area of triangle here:

https://brainly.com/question/19305981

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