At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Solution:
First, we need to draw a right triangle to represent the given trigonometric ratio. (Kindly refer to the attached photo for the figure.)
Second, we need to determine the length of the unknown side.
In this case, the unknown side is the hypotenuse. Since the length of the opposite side is 12 and the length of the adjacent side is 16, then the length of the hypotenuse is
[tex]c = \sqrt{16^{2} + 12^{2}}[/tex]
[tex]c = 20[/tex]
After this, we need to know the trigonometric identity of sin 2A in order to solve for its value.
We know that,
sin 2A = 2 sin A cos A
Then, we need to determine the values of sin A and cos A.
Based on the figure (attached photo), the values of sin A and cos A are
sin A = opposite side / hypotenuse
sin A = 12/20
sin A = 3/5
cos A = adjacent side / hypotenuse
cos A = 16/20
cos A = 4/5
Finally, we can now solve for the value of sin 2A by substituting the values of sin A and cos A to the trigonometric identity of sin 2A.
Therefore, the the value of sin 2A is
sin 2A = 2 sin A cos A
sin 2A = 2(3/5)(4/5)
sin 2A = 24/25
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.