Unikashrestha
Answered

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In the adjoining parallelogram ABCD, A is joined to any point E on BC. AE and DC produced meet at E Prove that. area of ∆BEF = area of ∆ CDE​

Sagot :

Akanksha49

Answer:

In parallelogram ABCD any point E is taken on the side BC . AE and DC when produced to meet at a point M . Prove that ar(ADM) = ar(ABMC) .
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