Answer:
12y+x = -20
Step-by-step explanation:
Question restructured
Identify the equation of the line that is perpendicular to y =12x−7 and runs through the point (4,−2).
The equation of a line in point-slope form is expressed as;
y-y0 = m(x-x0)
m is the slope
(x0,y0) is a point on the line
Given the equation y = 12x - 7
Slope = 12
Since the required line is perpendicular to this line, the slope of the required line will be;
m = -1/12
Get the required equation
y-(-2) = -1/12 (x - 4)
y+2= -1/12(x-4)
Cross multiply
12(y+2) = -(x-4)
12y+24 = -x+4
12y + x = 4-24
12y+x = -20
Hence the required equation is 12y+x = -20
NB: The equation of the line used in question was assumed
