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The quadratic function fhas a vertex at (3,4) and opens upward. The quadratic function g is shown below.
g(3) 2(1 – 4)² + 3
Which statement is true?
OA
The maximum value of fis greater than the maximum value of g.
The minimum value of gis greater than the minimum value of f.
O B.
Ос.
The minimum value of fis greater than the minimum value of g.
OD
The maximum value of g is greater than the maximum value of f.


The Quadratic Function Fhas A Vertex At 34 And Opens Upward The Quadratic Function G Is Shown Below G3 21 4 3 Which Statement Is True OA The Maximum Value Of Fi class=

Sagot :

Answer:

Option (C)

Step-by-step explanation:

Equation of the quadratic function having vertex at (3, 4) and opening upwards,

So the the minimum point of the function is (3, 4).

Therefore, minimum value of the function is 4 at x = 3.

y = (x - h)² + k [Here, (h, k) is the vertex]

g(x) = 2(x - 4)² + 3

Vertex of the parabola is (4, 3).

Since, leading coefficient is positive, parabola will open upwards.

Therefore, vertex will be the minimum point.

Minimum value of the function will be 3 at x = 4.

Minimum value of the function 'f' is greater than the minimum value of the function 'g'.

Option (C) will be the answer.

Answer:

C. The minimum value of f is greater than the minimum value of g.

Step-by-step explanation:

I got a 100% on my test

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