lm121704
Answered

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Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

Corsaquix

Answer:

[tex]x\approx 49.6^{\circ}[/tex]

Step-by-step explanation:

In any right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side.

For angle [tex]x[/tex]:

  • Opposite side is 40
  • Adjacent side is 34

Therefore, we have:

[tex]\tan x^{\circ}=\frac{40}{34}[/tex]

Take the inverse tangent of both sides to solve for [tex]x[/tex]:

[tex]\tan^{-1}(\tan x)=\tan^{-1}(\frac{40}{34}),\\x=\tan^{-1}(\frac{40}{34}),\\x=49.63546343\approx \boxed{49.6^{\circ}}[/tex]

*Recall [tex]\tan^{-1}(\tan x)=x\text{ for } x\in (-90^{\circ}, 90^{\circ})[/tex]

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