lm121704
Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

lhannearaujo

From one of the trigonometric ratios, tan(x), it is possible to find that x is equal to 52.1°.

Trigonometric Ratios

The main trigonometric ratios for a right triangle are presented below.

                [tex]sin(x)= \frac{opposite\; side}{hypotenuse} \\ \\ cos(x)= \frac{adjacent\; side}{hypotenuse} \\ \\tan(x)= \frac{sin(x)}{cos(x)} =\frac{opposite\; side}{hypotenuse}* \frac{adjacent\; side}{hypotenuse}=\frac{opposite\; side}{adjacent\; side}[/tex]

For solving this question, you need to apply the a trigonometric ratio . You have the dimensions of two sides and you need to find the angle x.

Thus, you can apply the tan(x).

                       [tex]tan(x)= \frac{opposite\; side}{adjacent\; side}=\frac{36}{28} =\frac{9}{7}[/tex]

After that, you should calculate the arctan(x).

                         

                           [tex]arctan\left(\frac{9}{7}\right)=52.1^{\circ \:}[/tex]

Then x= 52.1°

Learn more about trigonometric ratios here:

brainly.com/question/11967894

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.