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Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

lhannearaujo

From one of the trigonometric ratios, tan(x), it is possible to find that x is equal to 52.1°.

Trigonometric Ratios

The main trigonometric ratios for a right triangle are presented below.

                [tex]sin(x)= \frac{opposite\; side}{hypotenuse} \\ \\ cos(x)= \frac{adjacent\; side}{hypotenuse} \\ \\tan(x)= \frac{sin(x)}{cos(x)} =\frac{opposite\; side}{hypotenuse}* \frac{adjacent\; side}{hypotenuse}=\frac{opposite\; side}{adjacent\; side}[/tex]

For solving this question, you need to apply the a trigonometric ratio . You have the dimensions of two sides and you need to find the angle x.

Thus, you can apply the tan(x).

                       [tex]tan(x)= \frac{opposite\; side}{adjacent\; side}=\frac{36}{28} =\frac{9}{7}[/tex]

After that, you should calculate the arctan(x).

                         

                           [tex]arctan\left(\frac{9}{7}\right)=52.1^{\circ \:}[/tex]

Then x= 52.1°

Learn more about trigonometric ratios here:

brainly.com/question/11967894

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