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Hi, may someone help me with this question? Thank you!:)

“If f(x) = x^2 + 7, find f(x+2)”

Sagot :

wegnerkolmp2741o

Answer:

=x^2 +4x+11

Step-by-step explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

         = (x+2)(x+2) +7

     FOIL

     = x^2 +2x+2x+4 +7

Combine like terms

    =x^2 +4x+11

Corsaquix

Answer:

[tex]f(x+2)=x^2+4x+11[/tex]

Step-by-step explanation:

In [tex]f(x)=x^2+7[/tex], for all values of [tex]x[/tex], we substitute [tex]x[/tex] (what is in the parentheses) into [tex]x^2+7[/tex] to output a [tex]y[/tex] value.

In [tex]f(x+2)[/tex], the term [tex](x+2)[/tex] is in the parentheses. Therefore, substitute [tex](x+2)[/tex] for [tex]x[/tex] in [tex]x^2+7[/tex] to find [tex]f(x+2)[/tex]:

[tex]f(x+2)=(x+2)^2+7[/tex]

Expand using [tex](a+b)^2=a^2+2ab+b^2[/tex],

[tex]f(x+2)=x^2+4x+4+7[/tex]

Combine like terms:

[tex]\boxed{f(x+2)=x^2+4x+11}[/tex]

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