PandasZs
Answered

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I need help with my math!!!!!!!

I Need Help With My Math class=

Sagot :

CoastsideDad

Answer:

2[tex]\sqrt{6}[/tex]

Step-by-step explanation:

Area of a square = [tex]s^{2}[/tex]   (s is a side length)

24 = [tex]s^{2}[/tex]

[tex]\sqrt{24}[/tex] = [tex]\sqrt{s^{2} }[/tex]

[tex]\sqrt{24}[/tex] = s

[tex]\sqrt{(4)(6) }[/tex] = s

2[tex]\sqrt{6}[/tex] = s

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