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Sagot :
Answer:
(0, 2)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
Algebra I
- Coordinates (x, y)
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
Step 1: Define Systems
y = x + 2
3x + 3y = 6
Step 2: Solve for x
Substitution
- Substitute in y [2nd Equation]: 3x + 3(x + 2) = 6
- [Distributive Property] Distribute 3: 3x + 3x + 6 = 6
- Combine like terms: 6x + 6 = 6
- [Subtraction Property of Equality] Subtract 6 on both sides: 6x = 0
- [Division Property of Equality] Divide 6 on both sides: x = 0
Step 3: Solve for y
- Substitute in x [1st Equation]: y = 0 + 2
- Add: y = 2
Answer:
(0, 2)
Step-by-step explanation:
Since y is x + 2, we can replace y with x + 2
3x + 3y = 6
3x + 3(x+2) = 6
3x + 3x + 6 = 6
6x + 6 = 6
6x = 0
x = 0
y = x + 2
y = 2
Now we can check by replacing x with 0
3x + 3y = 6
3(0) + 3y = 6
0 + 3y = 6
3y = 6
y = 2
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