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Sagot :
Given:
[tex]m\angle ABC=65^\circ[/tex]
[tex]m\angle BCD=105^\circ[/tex]
To find:
Whether it is possible that Line AB intersects line CD.
Solution:
We have,
[tex]m\angle ABC=65^\circ[/tex]
[tex]m\angle BCD=105^\circ[/tex]
The angles [tex]m\angle ABC[/tex] and [tex]m\angle BCD[/tex] are same sided interior angles.
If two lines are parallel and a transversal line intersect them, then the same sided interior angles are supplementary angles and their sum is 180 degrees.
[tex]m\angle ABC+m\angle BCD=65^\circ+105^\circ[/tex]
[tex]m\angle ABC+m\angle BCD=170^\circ[/tex]
[tex]m\angle ABC+m\angle BCD\neq 180^\circ[/tex]
So, the lines AB and CD are not parallel to each other.
Therefore, the intersection of lines AB and CD is possible.
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