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Solve each system of equations by substitution. Clearly identify your solution.

Solve Each System Of Equations By Substitution Clearly Identify Your Solution class=

Sagot :

Space

Answer:

No solutions.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Algebra I

  • Coordinates (x, y)
  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x + 1

2x - y = 3

Step 2: Solve for x

Substitution

  1. Substitute in y [2nd Equation]:                                                                         2x - (2x + 1) = 3
  2. [Distributive Property] Distribute negative:                                                    2x - 2x + 1 = 3
  3. Combine like terms:                                                                                         1 ≠ 3

Answer:

The system has no solution.

Step-by-step explanation:

y = 2x + 1

2x - y = 3

  • substitute the given value of y into the equation 2x - y = 3.

2x - ( 2x +1) = 3

  • Distribute minus sign.

2x - 2x + 1 = 3

  • Combine like terms.

1 ≠ 3

Since system has no solution for x, the system has no solution.

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