Answer:
The equation of [tex]f(x) = e^{-3\cdot x}[/tex] by Maclaurin series is [tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3\cdot x)^{i}}{i!}[/tex].
Step-by-step explanation:
The Maclaurin series for [tex]f(x)[/tex] is defined by the following formula:
[tex]f(x) = \Sigma\limits_{i = 0}^{\infty} \frac{f^{(i)}(0)}{i!} \cdot x^{i}[/tex] (1)
Where [tex]f^{(i)}[/tex] is the i-th derivative of the function.
If [tex]f(x) = e^{-3\cdot x}[/tex], then the formula of the i-th derivative of the function is:
[tex]f^{(i)} = (-3)^{i}\cdot e^{-3\cdot x}[/tex] (2)
Then,
[tex]f^{(i)}(0) = (-3)^{i}[/tex] (2b)
Lastly, the equation of the trascendental function by Maclaurin series is:
[tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3)^{i}\cdot x^{i}}{i!}[/tex]
[tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3\cdot x)^{i}}{i!}[/tex] (3)
