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Sagot :
Let's see
[tex]\\ \tt\leadsto A=P(1+r/n)^{nt}[/tex]
- n=1
[tex]\\ \tt\leadsto A=1200(1+0.055)^t[/tex]
[tex]\\ \tt\leadsto A=1200(1.055)^t[/tex]
Answer:
[tex]\sf A=1200(1.055)^t[/tex]
Step-by-step explanation:
Annual Compound Interest Formula
[tex]\large \text{$ \sf A=P\left(1+r\right)^{t} $}[/tex]
where:
- A = final amount
- P = principal amount
- r = interest rate (in decimal form)
- t = time (in years)
Given:
- P = $1,200
- r = 5.5% = 0.055
- t = t years
Substitute the given values into the equation:
[tex]\implies \sf A=1200(1+0.055)^t[/tex]
[tex]\implies \sf A=1200(1.055)^t[/tex]
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