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A survey asks a random sample of 1500 adults in Ohio if they support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. Let ^ p denote the proportion in the sample who say they support the increase. Suppose that 47% of all adults in Ohio support the increase. The standard deviation of the sampling distribution is

Sagot :

Cricetus

Answer:

The correct response is "0.0129".

Step-by-step explanation:

Given:

[tex]n=1500[/tex]

[tex]p=0.47[/tex]

[tex]np=1500\times 0.47[/tex]

    [tex]=705[/tex]

[tex]nq=1500\times (1-0.47)[/tex]

    [tex]=795[/tex]

Mean of sampling distribution will be:

[tex]\mu_\hat{p}[/tex] = [tex]0.47[/tex]

hence,

The standard deviation will be:

⇒  [tex]\sigma_\hat{p}[/tex] = [tex]\sqrt{\frac{p(1-p)}{n} }[/tex]

By putting the values, we get

         = [tex]\sqrt{\frac{0.47(1-0.47)}{1500} }[/tex]

         = [tex]0.012886686[/tex]

         = [tex]0.0129[/tex]

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