Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Suppose y varies inversely with X, and y = 36 when x = 1/12. What inverse variation equation relates x and y?
NO LINKS OR ANSWERING YOU DON'T KNOW!!!

a. y= 3x
b. y= 3/x
c. x/3
d. y= x​


Sagot :

Answer:

B

Step-by-step explanation:

We are given that y varies inversely with x. Recall that inverse variation has the form:

[tex]\displaystyle y=\frac{k}{x}[/tex]

Where k is the constant of variation.

We are given that y = 36 when x = 1/12. Thus:

[tex]\displaystyle (36)=\frac{k}{\left({}^{1}\!/\!{}_{12}\right)}[/tex]

Solve for k. Multiply both sides by 1/12:

[tex]\displaystyle k=\frac{1}{12}(36)=3[/tex]

Hence, our equation is:

[tex]\displaystyle y=\frac{3}{x}[/tex]

Our answer is B.