Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

In a double-slit experiment, the slit spacing is 0.120 mm and the screen is 2.00 m from the slits. Find the wavelength (in nm) if the distance between the central bright region and the third bright fringe on a screen is 2.75 cm.

Sagot :

okpalawalter8

Answer:

[tex]\lambda=550nm[/tex]

Explanation:

From the question we are told that:

The slit spacing [tex]d_s=0.120mm=>0.120*10^{-3}[/tex]

Screen distance [tex]d_{sc}=2.0m[/tex]

Third Distance  [tex]X=2.75cm=>2.75*10^{-2}[/tex]

Generally the equation for Wavelength is mathematically given by

[tex]\lambda=\frac{Xd_s}{n*d_{sc}}[/tex]

Where

n=number of screens

[tex]n=3[/tex]

Therefore

[tex]\lambda=\frac{2.75*10^{-2}*0.120*10^{-3}}{3*2}[/tex]

[tex]\lambda=0.055*10^{-5}[/tex]

[tex]\lambda=550nm[/tex]

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.