Answer:
Slope = [tex]\frac{4}{3}[/tex]
Equation of the line → [tex]y=\frac{4}{3}x[/tex]
Step-by-step explanation:
Let the equation of diagonal OA is,
y = mx + b
Here, m = Slope of the line OA
b = y-intercept
Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,
m = [tex]\frac{4-0}{3-0}[/tex]
m = [tex]\frac{4}{3}[/tex]
Since, line OA is passing through the origin, y-intercept will be 0.
Therefore, equation of OA will be,
[tex]y=\frac{4}{3}x[/tex]
