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f(x) = square root 32x
g(x) = square root 2x

Fx Square Root 32x Gx Square Root 2x class=

Sagot :

Given:

The two functions are:

[tex]f(x)=\sqrt{32x}[/tex]

[tex]g(x)=\sqrt{2x}[/tex]

To find:

The [tex](f\cdot g)(x)[/tex]. Assume [tex]x\geq 0[/tex].

Solution:

We have,

[tex]f(x)=\sqrt{32x}[/tex]

[tex]g(x)=\sqrt{2x}[/tex]

Now,

[tex](f\cdot g)(x)=f(x)\cdot g(x)[/tex]

[tex](f\cdot g)(x)=\sqrt{32x}\cdot \sqrt{2x}[/tex]

[tex](f\cdot g)(x)=\sqrt{32x\times 2x}[/tex]

[tex](f\cdot g)(x)=\sqrt{64x^2}[/tex]

[tex](f\cdot g)(x)=8x[/tex]

Therefore, the correct option is A.