Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A 55 g soapstone cube--a whisky stone--is used to chill a glass of whisky. Soapstone has a density of 3000 kg/m3, whisky a density of 940 kg/m3. What is the approximate normal force of the bottom of the glass on a single stone?

Sagot :

okpalawalter8

Answer:

[tex]N=0.37N[/tex]

Explanation:

Mass [tex]m=55g=>0.055kg[/tex]

Soapstone Density [tex]\rho_s=3000kg/m^2[/tex]

Whisky Density [tex]\rho_w=940kg/m^2[/tex]

Generally the equation for Force is mathematically given by

 [tex]F=U+N[/tex]

Therefore

 [tex]N=m*g-(\frac{m}{\rho_s})*\rho_w*g[/tex]

 [tex]N=0.055*9.81 - {(\frac{0.055}{3000})*940*9.81}[/tex]

 [tex]N=0.37N[/tex]

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.