Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Write the sum of three odd consecutive integers if the last one is m-2

Sagot :

rvillalta2002

Answer:

the sum is 3m-12

Step-by-step explanation:

The nunbers are:

[tex]m-2\\m-4\\m-6\\the~sum~is:\\sum=(m-2)+(m-4)+(m-6)\\sum=m-2+m-4+m-6=m+m+m-2-4-6\\sum=3m-12[/tex]

The sum of three odd consecutive integers is 3m - 12

What are odd integers?

"These are the integers which are not divisible by 2."

For given question,

We need to find the sum of three consecutive odd integers.

Let x, x + 2, x + 4 be three consecutive odd integers.

We have been given the last one is m - 2

This means x + 4 = m - 2

So, the second odd integer would be,

x + 2 = m - 4

and the first odd integer would be,

x = m - 6

, we find the sum of the three odd consecutive integers.

⇒  (m - 6) + (m - 4) + (m - 2)

= m + m + m - 6 - 4 - 2

= 3m - (6 + 4 + 2)

= 3m - 12

Therefore, the sum of three odd consecutive integers is 3m - 12

Learn more about the odd integers here:

https://brainly.com/question/18365251

#SPJ2

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.