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Write the sum of three odd consecutive integers if the last one is m-2

Sagot :

rvillalta2002

Answer:

the sum is 3m-12

Step-by-step explanation:

The nunbers are:

[tex]m-2\\m-4\\m-6\\the~sum~is:\\sum=(m-2)+(m-4)+(m-6)\\sum=m-2+m-4+m-6=m+m+m-2-4-6\\sum=3m-12[/tex]

The sum of three odd consecutive integers is 3m - 12

What are odd integers?

"These are the integers which are not divisible by 2."

For given question,

We need to find the sum of three consecutive odd integers.

Let x, x + 2, x + 4 be three consecutive odd integers.

We have been given the last one is m - 2

This means x + 4 = m - 2

So, the second odd integer would be,

x + 2 = m - 4

and the first odd integer would be,

x = m - 6

, we find the sum of the three odd consecutive integers.

⇒  (m - 6) + (m - 4) + (m - 2)

= m + m + m - 6 - 4 - 2

= 3m - (6 + 4 + 2)

= 3m - 12

Therefore, the sum of three odd consecutive integers is 3m - 12

Learn more about the odd integers here:

https://brainly.com/question/18365251

#SPJ2

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