Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A circle is centered at the point (5,-4) and passes through the point (-3, 2). what is the equation of this circle?

Sagot :

Answer:

(x-5)² + (y+4)² = 100

Step-by-step explanation:

The formula for calculating the equation of a circle is expressed as;

(x-a)² + (y-b)² = r² where:

(a,b) is the centre of the circle

r is the radius

Get the radius using the distance formula;

r = √(2-(-4))²+(-3-5)²

r = √6²+(-8)²

r = √36+64

r =√100

r² = 100

Since a = 5 and b = -4, on substituting into the formula;

(x-5)² + (y+4)² = 100

This gives the required equation

Answer:

(x-5)² + (y+4)² = 100

Step-by-step explanation:

Just got it correct on Edmentum test.

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.