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Calculate how much disk space (in sectors, tracks, and surfaces) will be required to
store 300,000 120-byte logical records if the disk is fixed sector with 512 bytes/
sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore
any file header record(s) and track indexes, and assume that records cannot span
two sectors.

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Sagot :

Answer:

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View image sk5634943
View image sk5634943
Lanuel

The amount of disk space in sectors that would be required to store 300,000 records is equal to 75,000 sectors.

Given the following data:

  • Number of records = 300,000.
  • Size of each logical record = 120 byte.
  • Number of bytes (sector) = 512.
  • Number of sectors per track = 96.
  • Number of tracks per surface = 110.

How to calculate the required disk space?

First of all, we would determine the number of logical records that can be held by each sector as follows:

Number of logical records per sector = 512/120

Number of logical records per sector = 4.3 ≈ 4.0.

Now, we can calculate the required disk space to store 300,000 records:

Disk space = 300,000/4

Disk space = 75,000 sectors.

For the tracks, we have:

Disk space in tracks = 75,000/96

Disk space in tracks = 781.25 ≈ 782.

Disk space in tracks = 782 tracks.

For the surfaces, we have:

Disk space in surfaces = 782/110

Disk space in surfaces = 7.10 ≈ 8.

Disk space in surfaces = 8 surfaces.

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