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Calculate how much disk space (in sectors, tracks, and surfaces) will be required to
store 300,000 120-byte logical records if the disk is fixed sector with 512 bytes/
sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore
any file header record(s) and track indexes, and assume that records cannot span
two sectors.

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Sagot :

sk5634943

Answer:

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Lanuel

The amount of disk space in sectors that would be required to store 300,000 records is equal to 75,000 sectors.

Given the following data:

  • Number of records = 300,000.
  • Size of each logical record = 120 byte.
  • Number of bytes (sector) = 512.
  • Number of sectors per track = 96.
  • Number of tracks per surface = 110.

How to calculate the required disk space?

First of all, we would determine the number of logical records that can be held by each sector as follows:

Number of logical records per sector = 512/120

Number of logical records per sector = 4.3 ≈ 4.0.

Now, we can calculate the required disk space to store 300,000 records:

Disk space = 300,000/4

Disk space = 75,000 sectors.

For the tracks, we have:

Disk space in tracks = 75,000/96

Disk space in tracks = 781.25 ≈ 782.

Disk space in tracks = 782 tracks.

For the surfaces, we have:

Disk space in surfaces = 782/110

Disk space in surfaces = 7.10 ≈ 8.

Disk space in surfaces = 8 surfaces.

Read more on disk space here: https://brainly.com/question/26382243

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