Answered

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Which of the following is a solution to 2sin^(2)x+sinx-1=0
45\deg
200\deg
240\deg
270\deg
330\deg

Sagot :

caylus

Hello,

[tex]2*sin^2(x)+sin(x)-1=0\\\Delta=1+4*2*1=9=3^2\\sin^2(x)=\frac{-1-3}{4} =-1\ (impossible)\\or\\sin^2(x)=\frac{-1+3}{4} =\dfrac{1}{2}\\sin(x)=\dfrac{\sqrt{2} }{2} \Longrightarrow (x=45^o\ or\ x=135^o)\\or\\sin(x)=-\dfrac{\sqrt{2} }{2} \Longrightarrow (x=315^o\ or\ x=225^o)\\[/tex]

Answer A : 45°

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